A rocket is shot from the top of an oceanside cliff that is 60ft high. The original angle is 45 degrees and the original velocity is 50ft per sec. The formula for the rocket’s motion is:

y = f(x) = -0.0128x(squared) + x + 60

The variables x and y are both measured in feet. The variable x represents horizontal displacement (distance from the base of the cliff), and y represents the height of the rocket above the ground.

a) What is the maximum height attained by the rocket? How far has the rocket travelled horizontally at this point?

b) At waht point(s) (after launch) is the rocket 70 feet high? (Horizontal displacement)

c) How far away from the base of the cliff does the rocket land?

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