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Suppose you throw a baseball straight up at a velocity of 64 feet per second. A function can be created by expressing distance above ground, S, as a function, T.

This function is: S = -16T 2+ V0 T + S0 16 represents 1/2G, the gravitational pull due to gravity (measured in feet per second 2).

V0 is the initial velocity (How hard do you throw the object, measured in fet per second).

S0 is the initial distance above ground (in feet). If you are standing on the ground, then S0=0.

What is the function that describes this problem?

The ball will be how above ground after 1 second?

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